The internal resistance of the battery is high? That would explain why the voltage is high when there is no current but why there is no voltage when there is current.
The more current is drawn by the battery, the more voltage is dropped across the internal resistance and therefore the less voltage actually appears on the battery terminals.
My best guess is the cell has a very high internal resistance, If a cell is dropped, the surface plate can delaminate from the positive terminal, which makes the ESR shoot up, you might see if fall if you squeeze it gently
I cannot tell from your image what the mode your using in the first image is, but that does not look like a battery load option, could you clarify exactly what mode you have it set to there?